CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car is moving with a speed of 72 kmh−1 towards a roadside source that emits sound at a frequency of 850 Hz. The car driver listens to the sound while approaching the source and again while moving away from the source after crossing it. If the velocity of sound is 340 ms−1, the difference of the two frequencies, the driver hears is:

A
50 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
85 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
100 Hz
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
150 Hz
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 100 Hz
Given : Velocity of driver (observer) vo=72 km/h=20m/s
Actual frequency of the source ν=850Hz
Velocity of sound in air v=340m/s
Using Doppler effect when the observer moves towards the stationary source :
ν=ν[v+vov]=850[340+20340] ν=900Hz


Using Doppler effect when the observer moves away from the stationary source :
ν′′=ν[vvov]=850[34020340] ν=800Hz
Difference of the two frequency heard Δν=νν′′=900800=100Hz

496913_462125_ans_a7073c61f04e44dbaf111c7ef941aaba.png

flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
What Sound Really Is
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon