A car is moving with a velocity $20 m s^{- 1}$ . The brakes are applied to retard it at a rate of $2 m s^{- 2}$ . What will be the velocity after $5 s$ of applying the brakes?

30 m s^{- 1}

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2.5 m s^{- 1}

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5 m s^{- 1}

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10 m s^{- 1}

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Solution

The correct option is D $10 m s^{- 1}$
Acceleration, $a = \frac{v_{f i n a l} - v_{i n i t i a l}}{T i m e}$
Therefore, $- 2 m / s^{2} = \frac{v_{f i n a l} - 20 m / s}{5 s}$
$v_{f i n a l} = 10 m / s$

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A car is moving with a velocity 20 ms−1. The brakes are applied to retard it at a rate of 2 ms−2. What will be the velocity after 5s of applying the brakes?

The correct option is D 10ms−1Acceleration, a=vfinal−vinitialTimeTherefore, −2m/s2=vfinal−20m/s5svfinal=10m/s

A car is moving with a velocity $20 m s^{- 1}$ . The brakes are applied to retard it at a rate of $2 m s^{- 2}$ . What will be the velocity after $5 s$ of applying the brakes?

The correct option is D $10 m s^{- 1}$
Acceleration, $a = \frac{v_{f i n a l} - v_{i n i t i a l}}{T i m e}$
Therefore, $- 2 m / s^{2} = \frac{v_{f i n a l} - 20 m / s}{5 s}$
$v_{f i n a l} = 10 m / s$