A car moves along the periphery of a square field of side 10m. He completes travelling one side in 40s. What will be the magnitude of distance and displacement at the end of 2 min and 20 seconds?

35m, 35m

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35m, 5m

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25m, 10m

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35m, 10m

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Solution

The correct option is B
35m, 5m

Distance = speed $\times$ time
$= \frac{10}{40} \times 140$
$= 35 m$

Finding distance between initial and final position to find out displacement.
In travelling 35 m around a square of perimeter 40 m, the body is 5 m off its initial position.
So, its displacement will be 5 m.

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A car moves along the periphery of a square field of side 10m. He completes travelling one side in 40s. What will be the magnitude of distance and displacement at the end of 2 min and 20 seconds?

The correct option is B 35m, 5m Distance = speed × time =1040×140 =35 m Finding distance between initial and final position to find out displacement. In travelling 35 m around a square of perimeter 40 m, the body is 5 m off its initial position. So, its displacement will be 5 m.