A car moves along the periphery of a square field of side 10m. He completes travelling one side in 40s. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds?

35m, 35m

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35m, 5m

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25m, 10m

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35m, 10m

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Solution

The correct option is B
35m, 5m

Distance = speed $\times$ time
$= \frac{10}{40} \times 140$
$= 35 m$

Find the distance betw the en initial and final position to find out displacement.
While travelling 35m around of a square of perimeter 40m, the body is 5m off its initial position.
So, its displacement will be 5m.

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A car moves along the periphery of a square field of side 10m. He completes travelling one side in 40s. What will be the magnitude of distance and displacement at the end of 2min and 20 seconds?

The correct option is B 35m, 5m Distance = speed × time =1040×140 =35m Find the distance betw the en initial and final position to find out displacement. While travelling 35m around of a square of perimeter 40m, the body is 5m off its initial position. So, its displacement will be 5m.