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Question

# A car moves at a constant speed on a road as shown in figure. The normal force by the road on the car is NA and NB when it is at the points A and B respectively. Then?

A

NA = NB

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B

NA> NB

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C

NA< NB

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D

Insufficient information to decide the relation of NA and NB.

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Solution

## The correct option is C NA< NB ∴NA=mg−mv2RA NB=mg−mv2RR We see from the diagram that, the car traverses a much smaller curvature at A than at B. ∴RA<RB RA=mv2mg−NA,RB=mv2mg−NR mv2mg−NA<mv2mg−NB ⇒mg−NB<mg−NA ⇒−NB<NA ⇒NB>NA

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