A car moves north with a speed of $20 m s^{- 1}$ . It changes its direction to east and moves with a speed of $20 m s^{- 1}$ . What is its velocity now ?

20 m s^{- 1}

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40 m s^{- 1}

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10 m s^{- 1}

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20 \sqrt{2} m s^{- 1}

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Solution

The correct option is D $20 \sqrt{2} m s^{- 1}$

$- - \to A C ? A C^{2} = A B^{2} + B C^{2} A C = \sqrt{A B^{2} + B C^{2}} = \sqrt{20^{2} + 20^{2}} = 20 \sqrt{2} - - \to A C = 20 \sqrt{2} \frac{m}{s}$

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A car moves north with a speed of 20ms−1. It changes its direction to east and moves with a speed of 20ms−1. What is its velocity now ?

The correct option is D 20√2ms−1 −−→AC?AC2=AB2+BC2AC=√AB2+BC2=√202+202=20√2−−→AC=20√2ms

A car moves north with a speed of $20 m s^{- 1}$ . It changes its direction to east and moves with a speed of $20 m s^{- 1}$ . What is its velocity now ?

The correct option is D $20 \sqrt{2} m s^{- 1}$

$- - \to A C ? A C^{2} = A B^{2} + B C^{2} A C = \sqrt{A B^{2} + B C^{2}} = \sqrt{20^{2} + 20^{2}} = 20 \sqrt{2} - - \to A C = 20 \sqrt{2} \frac{m}{s}$