A car moves with $90 k m / h$ for $30 m i n$ and with $18 m / s$ for $1 h r$ later on with $60 k m / h r$ for $45 m i n$ . Find the distance covered by car during the whole journey and calculate average.

Open in App

Solution

Total distance covered $= 90 \times \frac{1}{2} + \frac{18 \times 3600}{1000} + \frac{60}{3600} \times 45 \times 60$
$= (45 k m + 64.8 + 45) k m$
$= (90 k m + 64.8) k m$
$= 154.8 k m$

Suggest Corrections

Similar questions

A car moves with a speed of 40 km/hr for 15 minutes and then with a speed of 60 km/hr for the next 15 minutes. What is the total distance covered by the car? Also, find the average speed of the car. [5 MARKS]

A car travels 100 km at a speed of 60 km/h and returns with a speed of 40 km/h. Calculate the average speed for the whole journey.

A truck moves with a speed of 30 km/h for 2 h 30 min. What is the total distance covered by the truck during the whole journey?

Q. One car moving on a straight road cover one third of the distance with

20 k m / h r

and the rest with

60 k m / h r

. The average speed of the car is

Q. A car moves for half of its time at

80 K m / h r

and for rest of time

40 K m / h r

. If total distance covered is

60 K m,

the average sped of the car is:

Join BYJU'S Learning Program

A car moves with 90 km/h for 30 min and with 18 m/s for 1 hr later on with 60 km/hr for 45 min. Find the distance covered by car during the whole journey and calculate average.

Total distance covered =90×12+18×36001000+603600×45×60 =(45km+64.8+45)km=(90km+64.8)km=154.8km

A car moves with $90 k m / h$ for $30 m i n$ and with $18 m / s$ for $1 h r$ later on with $60 k m / h r$ for $45 m i n$ . Find the distance covered by car during the whole journey and calculate average.

Total distance covered $= 90 \times \frac{1}{2} + \frac{18 \times 3600}{1000} + \frac{60}{3600} \times 45 \times 60$
$= (45 k m + 64.8 + 45) k m$
$= (90 k m + 64.8) k m$
$= 154.8 k m$