A car moves with a constant velocity of 10ms−1 for 10 s along a straight road. Then it moves with uniform acceleration of 2ms−2 for 5 seconds. Find the total displacement at the end of the 15 s of its motion.
A
175 m
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B
125 m
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C
150 m
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D
105 m
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Solution
The correct option is A175 m
For constant velocity :
Constant velocity u=10m/s
Time t=10s
So, displacement in 10 seconds S1=ut=10×10=100m
For accelerated journey :
Initial speed u=10m/s
Acceleration a=2m/s2
Time t=5s
Displacement in 5 seconds, S2=ut+12at2
⟹S2=10×5+12×2×52=75m
Total displacement in 15 seconds Stotal=100+75=175m