Question

A car moving around a circular track of $200$ m radius increasing its speed of $2$m/s second. The speed of the car when the acceleration of the car is $4m/s^2$ is

• A. $10m/s$
• B. $16.25m/s$
• C. $24.64m/s$
• D. $26.32m/s$

Answer 1

The correct option is D $26.32m/s$

As acceleration of car is changing from $\frac{2m}{S^2}$ to $\frac{4m}{s^2}$

Change of acceleration is $\sqrt{(}{4}^2–2^2)=\sqrt{1}2$

Therefore a=$\frac{3.46m}{s^2}$

As we know F=ma___(1),

F=$\frac{m{v}^2}{r}$___(2)

Solve equation 1&2

a=$\frac{v^2}{r}$

3.46$\times 200=v^2$

$V^2$=692.83

V=26.32m/s