Question

A car moving is with a particular velocity, which has been measured each second and the data is recorded as per the table below.
Velocity Time
$0$ $0$
$2m/s$ $1s$
$4m/s$ $2s$
$6m/s$ $3s$
$8m/s$ $4s$
Calculate the acceleration of the car ?

• A. $1m/s^2$
• B. $2m/s^2$
• C. $4m/s^2$
• D. $6m/s^2$
• E. $8m/s^2$

Answer 1

The correct option is B $2m/s^2$

Acceleration is defined as the ratio of change in velocity to the change in time interval.

Acceleration $a=\frac{\Delta v}{\Delta t}$

The given data shows that the velocity of car changes by $2m/s$ in $1$ $s$ each.

Thus acceleration of the car $a=\frac{\Delta v}{\Delta t}=\frac{2}{1}=2m/s^2$