The correct option is B 1.5 m/s2
Initial velocity (u)=54 km/h
Final velocity (v)=0 m/s
Time interval t=10 s
We have,
Initial velocity (u)=54 km/h
=54×518=15 m/s
Final velocity (v)=0 m/s
Time interval t=10 s
We have, a=v−ut=0−1510=−1.5 m/s2
Here, negative signs show retardation
∴ The magnitude of average retardation =1.5 m/s2