A car moving with a velocity of 10m/s can be stopped by the application of a constant force F in a distance of 20m. If the velocity of the car is 30m/s, it can be stopped by this force in
A
203m
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B
20m
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C
60m
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D
180m
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Solution
The correct option is D180m Since, the applied force is constant, the retardation produce by it in order to stop the car will be constant. We have, v2−u2=2as⇒02−u2=−2as ⇒s∝u2. ⇒s2s1=u22u21⇒s220=302102 ⇒s2=180m Hence, in second condition the car will stop in a distance of s2=180m