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Byju's Answer

Standard IX

Physics

Second Law of Motion

A car of mass...

Question

A car of mass $100 k g$ travelling at $32 m / s$ clashes into a rear of a truck of mass $8000 k g$ moving in the same direction with a velocity of $4 m / s$ . After the collision the car bounces with a velocity of $8 m s^{- 1}$ . The velocity of truck after the impact is _______ m/s.

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Solution

The correct option is D $9$
Correct option is $(D)$
As we know due to no external force momentum is conserved
$\begin{matrix} P_{i} & = P_{f} M_{C} V_{C} + M_{T} V_{T} & = M_{C} V_{c} + M_{T} V_{T} (1000 \times 32) + (8000 \times 4) & = [1000 \times - (8)] + 8000 V_{T} \end{matrix}$
on solving this;

$V_{T} = 9 m / s$

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A car of mass 100kg travelling at 32m/s clashes into a rear of a truck of mass 8000kg moving in the same direction with a velocity of 4m/s. After the collision the car bounces with a velocity of 8ms−1. The velocity of truck after the impact is _______ m/s.

The correct option is D 9Correct option is (D) As we know due to no external force momentum is conserved Pi=PfMCVC+MTVT=MCVc+MTVT(1000×32)+(8000×4)=[1000×−(8)]+8000VT on solving this; VT=9 m/s

A car of mass $100 k g$ travelling at $32 m / s$ clashes into a rear of a truck of mass $8000 k g$ moving in the same direction with a velocity of $4 m / s$ . After the collision the car bounces with a velocity of $8 m s^{- 1}$ . The velocity of truck after the impact is _______ m/s.