A car of mass 1000 kg is moving with a velocity of $v = 10 m s^{- 1}$ . If the velocity-time graph for this car is a horizontal line parallel to the time axis, then the velocity of car at the end of 25 s will be :

(a) $25 m s^{- 1}$

(b) $40 m s^{- 1}$

(c) $10 m s^{- 1}$

(d) $250 m s^{- 1}$

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Solution

Given Data:

Mass of the car,
$m = 1000 k g$
Velocity of the car, $v = 10 m s^{- 1}$
Since, the velocity-time graph for this car is a horizontal line parallel to the time axis, it means velocity will remain constant with respect to time.

Hence, The velocity of the car is 10m/s after 25sec

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A car of mass 1000 kg is moving with a velocity of v=10ms−1 . If the velocity-time graph for this car is a horizontal line parallel to the time axis, then the velocity of car at the end of 25 s will be : (a) 25 m s−1 (b) 40 m s−1 (c) 10 m s−1 (d) 250 m s−1

Given Data: Mass of the car, m=1000kgVelocity of the car, v=10ms−1 Since, the velocity-time graph for this car is a horizontal line parallel to the time axis, it means velocity will remain constant with respect to time.Hence, The velocity of the car is 10m/s after 25sec

A car of mass 1000 kg is moving with a velocity of $v = 10 m s^{- 1}$ . If the velocity-time graph for this car is a horizontal line parallel to the time axis, then the velocity of car at the end of 25 s will be :

(a) $25 m s^{- 1}$

(b) $40 m s^{- 1}$

(c) $10 m s^{- 1}$

(d) $250 m s^{- 1}$

Given Data:

Mass of the car,
$m = 1000 k g$
Velocity of the car, $v = 10 m s^{- 1}$
Since, the velocity-time graph for this car is a horizontal line parallel to the time axis, it means velocity will remain constant with respect to time.

Hence, The velocity of the car is 10m/s after 25sec