A car of mass $1, 000 k g$ moving with a velocity of $40 k m h^{- 1}$ collides with a tree and comes to a stop in $5 s$ . What will be the force exerted by car on the tree?

2222.22 N

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1111.11 N

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3333.33 N

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None of the above

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Solution

The correct option is A $2222.22 N$
$v = u + a t$
$a = \frac{v - u}{t}$
$F = m a = \frac{m (v - u)}{t}$
$= \frac{1000 (0 - \frac{40 \times 1000}{3600})}{5}$
$= \frac{- 20000}{9}$
$= - 2222.22 N$

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A car of mass 1,000 kg moving with a velocity of 40 km h−1 collides with a tree and comes to a stop in 5 s. What will be the force exerted by car on the tree?

The correct option is A 2222.22 Nv=u+ata=v−utF=ma=m(v−u)t =1000(0−40×10003600)5 =−200009 =−2222.22N

A car of mass $1, 000 k g$ moving with a velocity of $40 k m h^{- 1}$ collides with a tree and comes to a stop in $5 s$ . What will be the force exerted by car on the tree?

The correct option is A $2222.22 N$
$v = u + a t$
$a = \frac{v - u}{t}$
$F = m a = \frac{m (v - u)}{t}$
$= \frac{1000 (0 - \frac{40 \times 1000}{3600})}{5}$
$= \frac{- 20000}{9}$
$= - 2222.22 N$