A car of mass $1250$ kg is moving at $30$ m/s. Its engine delivers $30$ kW while resistive force due to surface is $750$ N. What max acceleration can be given to the car?

\frac{1}{3} m / s^{2}

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\frac{1}{4} m / s^{2}

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\frac{1}{5} m / s^{2}

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\frac{1}{6} m / s^{2}

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Solution

The correct option is C $\frac{1}{5} m / s^{2}$
Force produced by engine $F = \frac{p}{v} = \frac{30 \times 10^{3}}{30} = 1030$

Accleration $= \frac{f o r w a r d f o r c e b y e n g i n e - r e s i s t i v e f o r c e}{m a s s o f c a r}$

$\frac{1000 - 750}{1250}$

$= \frac{250}{1250}$

$= \frac{1}{5} \frac{m}{s^{2}}$

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A car of mass 1250 kg is moving at 30 m/s. Its engine delivers 30 kW while resistive force due to surface is 750N. What max acceleration can be given to the car?

The correct option is C 15m/s2Force produced by engine F=pv=30×10330=1030Accleration=forward force by engine−resistive forcemass of car1000−7501250 =2501250 =15ms2

A car of mass $1250$ kg is moving at $30$ m/s. Its engine delivers $30$ kW while resistive force due to surface is $750$ N. What max acceleration can be given to the car?