A car of mass $1800 k g$ moving with a speed of $10 m / s$ is brought to rest after a Covering a distance of $50 m$ . Calculate the force acting on the car.

1800 N

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900 N

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3600 N

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1600 N

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Solution

The correct option is A $1800 N$
Given,
$M = 1800 k g$
$u = 10 m s^{- 1}$
$s = 50 m$
$F = ?$
We know that
$V^{2} - u^{2} = 2 a s$

$0 - (10)^{2} = 2 a \times 50 m$

$a = \frac{- 100}{100} = - 1 m s^{- 2}$

$F = m a$
Therefore, deceleration $= - 1 m / s^{2}$

$D e c e l e r a t i o n = - (a c c e l e r a t i o n)$

$F = 1800 \times 1 m s^{- 2}$
$= 1800 N$
Force will be acting in the opposite direction to a displacement of the car

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A car of mass 1800 kg moving with a speed of 10m/s is brought to rest after a Covering a distance of 50 m. Calculate the force acting on the car.

The correct option is A 1800 NGiven,M=1800kgu=10ms−1s=50mF=?We know that V2−u2=2as0−(10)2=2a×50ma=−100100=−1ms−2F=maTherefore, deceleration=−1m/s2Deceleration=−(acceleration)F=1800×1ms−2=1800NForce will be acting in the opposite direction to a displacement of the car

A car of mass $1800 k g$ moving with a speed of $10 m / s$ is brought to rest after a Covering a distance of $50 m$ . Calculate the force acting on the car.