A car of mass $2000 k g$ travelling with a uniform velocity of $2 m s^{- 1}$ accelerates till its velocity becomes $22 m s^{- 1}$ . The work done on the car is

$4.8 K J$

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$480 K J$

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$48 K J$

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$500 K J$

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Solution

The correct option is B
$480 K J$

Step 1: Given data
Mass of the car $m$ = $2000 k g$
Initial velocity $v_{1}$ = $2 m s^{- 1}$
Final velocity $v_{2}$ = $22 m s^{- 1}$
Step 2: To find the work done on the car.
The work-energy theorem states that the work done is equal to the change in Kinetic energy $(K . E)$ .
$K . E$ = $\frac{1}{2} m ({v_{2}}^{2} - {v_{1}}^{2})$
$K . E$ = $\frac{1}{2} \times 2000 \times (22^{2} - 2^{2})$
$K . E$ = $480000 J$ = $480 K J$
Therefore, the work done on the car is $480 K J$ .
Hence Option B is correct.

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