wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A car starts at P, and travels at a speed of 50 km h1 for 6 hours. It comes to rest at Q. 2 hours after the first car starts, another car starts at P and moves towards Q.
In order to reach the point Q at the same time as the first car, with what speed must the second car travel?

A
65 km h1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
75 km h1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
85 km h1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
55 km h1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 75 km h1
Given:
Speed of first car = 50 km h1
Time travelled by the first car = 6 h.

Distance between P and Q = 50×6=300 km

Now, the second car starts 2 hours after the first car.
To reach the point Q at the same time as the first car, the second car should cover the distance between P and Q in the remaining time.

Distance to be covered = 300 km
Remaining time = 6 - 2 = 4 h

Required speed = 3004 = 75 km h1

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Average speed
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon