Question

A car states from rest and acquires a velocity of $54km/hr$ in $2$ minutes. Find(i) acceleration and(ii) distance travelled by car in this time. Assume, that the motion of the car is uniform.

Answer 1

Given that,

Intial velocity $u=0m/s$

Final velocity $v=54km/h=54\times \frac{5}{18}=15m/s$

Time $t=2min=120s$

Now, put the value in equation of motion

The acceleration is

$v=u+at$

$a=\frac{v-u}{t}$

$a=\frac{15-0}{120}$

$a=o.125m/s^2$

Now, again from equation of motion

The distance is

$s=ut+\frac{1}{2}a{t}^2$

$s=0+\frac{1}{2}\times 0.125\times 120\times 120$

$s=900m$

Hence, the acceleration is $0.125m/s^2$ and distance is $900m$