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Byju's Answer
Standard XII
Chemistry
1900's Physics and Wave
A car traveli...
Question
A car traveling at
22.4
m
/
s
skids to a stop in
2.55
s
. Determine the skidding distance of the car (assume uniform acceleration).
A
28.6
m
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B
286
m
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C
276
m
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D
27.6
m
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Solution
The correct option is
D
28.6
m
Here, initial velocity,
u
=
22.4
m
/
s
and final velocity,
v
=
0
m
/
s
Time taken by car to stop
t
=
2.55
s
If
a
be the acceleration.
Using formula
v
=
u
+
a
t
,
0
=
22.4
+
a
(
2.55
)
We get
a
=
−
8.78
m
/
s
2
(negative signs means deceleration of car)
If
d
be the distance traveled by car.
Using formula
v
2
−
u
2
=
2
a
d
0
2
−
(
22.4
)
2
=
2
(
−
8.78
)
d
⟹
d
=
28.6
m
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