A car traveling at a speed of 20m/s due north along the way makes a right turn on to a side road that heads to east. It takes 50 sec for the car to complete the turn. At the end of the 50s, the car has the speed of 15m/s along the side road. Determine the magnitude of average acceleration over the 50s interval.
The car initially travls at 20 j (m/s).
At the end of 50 seconds the velocity becomes 15 i.
Therefore acceleration along x = 15-0/time = 15/50 = 0.3 i
Acceleration along y = 0-20/time = -20/50= -0.4j
Thus th total acceleration is 0.3i +0.4j.
thus the magnitude is 0.5