A car travelled from city A to city B and returned back to city A in 30 minutes. The distance between city A and city B is 10 km. The average speed and average velocity of the car will be respectively (in m/s):

11.11, 0

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0, 11.11

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0, 0

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11.11, 11.11

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Solution

The correct option is A 11.11, 0
Total distance covered:
$d = 2 \times 10 k m$
$d = 20000 m$

Time taken:
$t = 30 m i n$
$t = 30 \times 60 s = 1800 s$

Average speed is given by:
$< v >= \frac{d}{t}$
$< v >= \frac{20000 m}{1800 s}$
$< v >= 11.11 m / s$

Since the car returns to the initial position, displacement $(s)$ is 0.
Average velocity is given by:
$v_{a v g} = \frac{s}{t} = 0$

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A car travelled from city A to city B and returned back to city A in 30 minutes. The distance between city A and city B is 10 km. The average speed and average velocity of the car will be respectively (in m/s):

The correct option is A 11.11, 0Total distance covered: d=2×10 km d=20000 m Time taken: t=30 min t=30×60 s=1800 s Average speed is given by: <v>=dt <v>=20000 m1800 s <v>=11.11 m/s Since the car returns to the initial position, displacement (s) is 0. Average velocity is given by: vavg=st=0