A car travels first 150 km at 30 km/h and the next 120 km at 40 km/h. Its average speed is:

30.25 km/h

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35.55 km/h

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33.75 km/h

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38.65 km/h

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Solution

The correct option is C 33.75 km/h
$T i m e t a k e n f o r f i r s t s p e e d = \frac{D i s t a n c e}{S p e e d}$
$= \frac{150 k m}{30 k m / h} = 5 h o u r s$
$T i m e t a k e n f o r n e x t s p e e d = \frac{D i s t a n c e}{S p e e d}$
$= \frac{120 k m}{40 k m / h} = 3 h o u r s$
$T o t a l t i m e t a k e n = 3 h o u r s + 5 h o u r s$
$= 8 h o u r s$
$T o t a l d i s t a n c e = 150 k m + 120 k m$
$= 270 k m$
$A v e r a g e s p e e d = \frac{T o t a l d i s t a n c e t r a v e l l e d}{T o t a l t i m e t a k e n}$
$= \frac{270 k m}{8 h o u r s} = 33.75 k m / h$

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