A car travels first 30 km with a uniform speed of $60 k m h^{- 1}$ and then next 30 km with a uniform speed of $40 k m h^{- 1}$ . Calculate the total time of journey,

50 min

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75 min

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60 min

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100 min

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Solution

The correct option is B 75 min
$T i m e = \frac{D i s t a n c e}{S p e e d}$
For first 30 km, $t_{1} = \frac{30 k m}{60 k m / h} = \frac{1}{2} h = 30 m i n$
For next 30 km, $t_{2} = \frac{30 k m}{40 k m / h} = \frac{3}{4} h = 45 m i n$
Therefore, Total time of journey, $t = t_{1} + t_{2} = 30 m i n + 45 m i n = 75 m i n$

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A car travels first 30 km with a uniform speed of 60 kmh−1 and then next 30 km with a uniform speed of 40 kmh−1. Calculate the total time of journey,

The correct option is B 75 minTime=DistanceSpeedFor first 30 km, t1=30km60km/h=12h=30minFor next 30 km, t2=30km40km/h=34h=45minTherefore, Total time of journey, t=t1+t2=30min+45min=75min

A car travels first 30 km with a uniform speed of $60 k m h^{- 1}$ and then next 30 km with a uniform speed of $40 k m h^{- 1}$ . Calculate the total time of journey,