A car travels on a straight road for 30 km at 60 km/hr and then 80 km/hr in the opposite direction for half of an hour. What is its average velocity ?

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Solution

Dear Student ,
$a v e r a g e v e l o c i t y = \frac{t o t a l d i s p l a c e m e n t}{t o t a l t i m e} = \frac{30 - 40}{\frac{1}{2} + \frac{1}{2}} = \frac{- 10}{1} k m / h o r 10 k m / h i n o p p o s i t e d i r e c t i o n$
Regard

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A car travels on a straight road for 30 km at 60 km/hr and then 80 km/hr in the opposite direction for half of an hour. What is its average velocity ?

Dear Student , average velocity =total displacement total time=30-4012+12=-101km/hor 10km/h in opposite direction Regard

Dear Student ,
$a v e r a g e v e l o c i t y = \frac{t o t a l d i s p l a c e m e n t}{t o t a l t i m e} = \frac{30 - 40}{\frac{1}{2} + \frac{1}{2}} = \frac{- 10}{1} k m / h o r 10 k m / h i n o p p o s i t e d i r e c t i o n$
Regard