A car travels with a uniform velocity of $25 m s^{- 1}$ for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. The distance which the car travels before the brakes are applied is equal to

250 m

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125 m

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0 m

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62.5 m

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Solution

The correct option is B 125 m
The distance covered by the car before the brakes are applied is
$D i s t a n c e = V e l o c i t y \times T i m e = 25 \times 5 = 125 m / s$

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A car travels with a uniform velocity of 25ms−1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. The distance which the car travels before the brakes are applied is equal to

The correct option is B 125 mThe distance covered by the car before the brakes are applied is Distance=Velocity×Time=25×5=125 m/s

A car travels with a uniform velocity of $25 m s^{- 1}$ for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. The distance which the car travels before the brakes are applied is equal to

The correct option is B 125 m
The distance covered by the car before the brakes are applied is
$D i s t a n c e = V e l o c i t y \times T i m e = 25 \times 5 = 125 m / s$