A car travels with a uniform velocity of $25 m s^{- 1}$ for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find the distance travelled by the car after applying the brakes.

25 m

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625 m

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125 m

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0 m

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Solution

The correct option is D $125 m$
$v = u + a t$
$0 = 25 + 10 a$
$a = - 2.5 m / s^{2}$

The distance traveled by the car after applying the brakes,
$s = u t + \frac{1}{2} a t^{2}$
$s = 25 \times 10 + \frac{1}{2} \times (- 2.5) \times (10^{2})$
$s = 125 m$

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A car travels with a uniform velocity of 25 ms−1 for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find the distance travelled by the car after applying the brakes.

The correct option is D 125 mv=u+at0=25+10aa=−2.5 m/s2The distance traveled by the car after applying the brakes,s=ut+12at2s=25×10+12×(−2.5)×(102)s=125 m

A car travels with a uniform velocity of $25 m s^{- 1}$ for 5 s. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 s. Find the distance travelled by the car after applying the brakes.

The correct option is D $125 m$
$v = u + a t$
$0 = 25 + 10 a$
$a = - 2.5 m / s^{2}$

The distance traveled by the car after applying the brakes,
$s = u t + \frac{1}{2} a t^{2}$
$s = 25 \times 10 + \frac{1}{2} \times (- 2.5) \times (10^{2})$
$s = 125 m$