A car travels with the uniform velocity of 25 m/s for five seconds. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 seconds. Find:
1)The distance which the car travelled before the brakes are applied
2)The retardation
3)The distance travelled b

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Solution

U=25m/sec
Distance it travels in 5sec
Distance travelled before the brakes are applied= 255=125m
After 5 sec brakes are applied
It then comes to rest in 10sec
u=25m/s
v=0(as it comes to rest)
t=10
a=change in velocity/time=-25/10=-2.5
s=?
s=ut+at^2/2
s=2510+(-2.5)(100)/2=250-125
The distance it travels after the brakes are applied is 125m

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A car travels with the uniform velocity of 25 m/s for five seconds. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 seconds. Find: 1)The distance which the car travelled before the brakes are applied 2)The retardation 3)The distance travelled b

A car travels with the uniform velocity of 25 m/s for five seconds. The brakes are then applied and the car is uniformly retarded and comes to rest in further 10 seconds. Find:
1)The distance which the car travelled before the brakes are applied
2)The retardation
3)The distance travelled b