A carbohydrate $X$ having molecular weight $180 g {m o l}^{- 1}$ has one primary alcohol group and four secondary alcoholic groups. It reacts with acetic anhydride to form pentaacetate. The molecular weight of pentaacetate formed is:

180

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210

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390

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42

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Solution

The correct option is D $390$
X is Glucose.
The Weight of Glucose Pentaacetate formed is 390

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Similar questions

Q. A comppound of molecular wight

180

is acetylated to give a compound of molecular weight

390

. The number of Alcoholic groups in the compound is:

Q. How many moles of acetic anhydride will be required to form glucose pentaacetate from

2 M

of glucose?

Which of the following reactions of glucose can be explained only by its cyclic structure?
(a) Glucose forms pentaacetate
(b) Blucose reacts with hydoxylamine to form an oxime
(c) Pentaacetate of glucose does not reach with hydroxyl amine
(d) Glucose is oxidised by nitric acid to gluconic acid

Q. Primary and secondary amines react with acid chloride or acid anhydride to form:

How do you explain
the absence of aldehyde group in the pentaacetate of D-glucose?

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A carbohydrate X having molecular weight 180gmol−1 has one primary alcohol group and four secondary alcoholic groups. It reacts with acetic anhydride to form pentaacetate. The molecular weight of pentaacetate formed is:

The correct option is D 390X is Glucose.The Weight of Glucose Pentaacetate formed is 390

A carbohydrate $X$ having molecular weight $180 g {m o l}^{- 1}$ has one primary alcohol group and four secondary alcoholic groups. It reacts with acetic anhydride to form pentaacetate. The molecular weight of pentaacetate formed is:

The correct option is D $390$
X is Glucose.
The Weight of Glucose Pentaacetate formed is 390