A cardboard create is 6 dm long- 3-4 dm wide and 3 dm high- Find its total surface area in cm2 and dm2- If the total crate surface is 56 of the total cardboard surface used to construct the box- how much cardboard was used-

Total surface area [ =2( lw+wh+hl ) #160;; =2( 6× 3.4+3.4× 3+3× 6 ) ...

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Standard VI

Mathematics

Area of Square

A cardboard c...

Question

A cardboard create is $6 d m$ long, $3.4 d m$ wide and $3 d m$ high. Find its total surface area in $c m^{2}$ and $d m^{2}$ . If the total crate surface is $\frac{5}{6}$ of the total cardboard surface used to construct the box, how much cardboard was used?

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Solution

Total surface area
$\begin{matrix} = 2 (l w + w h + h l) = 2 (6 \times 3.4 + 3.4 \times 3 + 3 \times 6) = 2 (20.4 + 0.2 + 18) = 97.20 d m^{2} = 9720 d m^{2} \end{matrix}$

Total cardboard used
$\begin{matrix} = \frac{5}{6} \times 9720 = 81 d m^{2} = 0.81 d m^{2} \end{matrix}$

Hence, this is the answer.

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A cardboard create is 6 dm long, 3.4 dm wide and 3 dm high. Find its total surface area in cm2 and dm2. If the total crate surface is 56 of the total cardboard surface used to construct the box, how much cardboard was used?

Total surface area=2(lw+wh+hl)=2(6×3.4+3.4×3+3×6)=2(20.4+0.2+18)=97.20 dm2=9720 dm2Total cardboard used =56×9720=81 dm2=0.81dm2Hence, this is the answer.

A cardboard create is $6 d m$ long, $3.4 d m$ wide and $3 d m$ high. Find its total surface area in $c m^{2}$ and $d m^{2}$ . If the total crate surface is $\frac{5}{6}$ of the total cardboard surface used to construct the box, how much cardboard was used?