A carnot engine absorbs 1000 J of heat energy from a reseruoire at $127^{\circ} C$ and reject 600 J of heat energy during each cycle of calculate
(i) Efficiency of engine
(ii) Temperature of sink $T_{2}$
(iii) amount of useful work done bar

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Solution

Q1 = 1000 J taking from source

Q2 = 600 J to sink

W = useful work done per cycle = Q1 - Q2 = 400 J

η = efficiency of the Carnot engine = W / Q1 =(Q1 - Q2)/ Q1 100 = 40%

T1 = 127° C = 400°K

Q1 / Q2 = T1/T2 => 1000/600 = 400/T2

T2 = 240°K = - 33 °C

Alternately, η = 0.4 = (T1 - T2)/T1

So T1 - T2 = 4000.4 = 160 K

T2 = 240 K

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A carnot engine absorbs 1000 J of heat energy from a reseruoire at 127∘C and reject 600 J of heat energy during each cycle of calculate(i) Efficiency of engine(ii) Temperature of sink T2(iii) amount of useful work done bar

A carnot engine absorbs 1000 J of heat energy from a reseruoire at $127^{\circ} C$ and reject 600 J of heat energy during each cycle of calculate
(i) Efficiency of engine
(ii) Temperature of sink $T_{2}$
(iii) amount of useful work done bar