Question

A carnot engine operates between ${327}^0$ C and ${27}^0$ C . How much heat does it take from the ${327}^0$ C reservoir for every 100 J of work done ?

• A. 100 J
• B. 200 J
• C. 300 J
• D. 400 J

Answer 1

The correct option is B 200 J

The temperature in kelvin scales are $T_2=273+27=300K,T_1=273+337=600K$

$T_1$is temperature of sink And$T_2$ is temperature of source hence by efficiency we get

$\eta =1-\frac{T_1}{T_2}=1-\frac{Q_1}{Q_2}$

$Q_1=\frac{T_1}{T_2}\ast Q_2=\frac{600}{300}\ast 100=200kW$