A Carnot engine works between ice point and steam point. Its efficiency will be

26.81%

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

53.36%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

71.23%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

85.42%

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 26.81%
Ice point $= 0^{o}$ C
Steam point $= 100^{o}$ C
Efficiency $= 1 - \frac{T_{c}}{T_{h}} = 1 - \frac{273}{373} = 1 - 0.732 = 0.268$

Suggest Corrections

Similar questions

Efficiency of Carnot engine working between ice point and steam point would be

20

Join BYJU'S Learning Program