wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A cathode emits 1.8×1014 electrons per second when heated. When 400V is applied to anode all the emitted electrons reach the anode. The charge on electron is 1.6×1019C The maximum anode current is

A
2.7μA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
29μA
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
72μA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
29mA
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 29μA
As we know,
i=Qt=net=1.8×1014×1.6×1019=28.8×106A
=29μA

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Electric Field
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon