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Question

A cathode emits 1.8×1014 electrons per second when heated. When 400V is applied to anode all the emitted electrons reach the anode. The charge on electron is 1.6×1019C The maximum anode current is

A
2.7μA
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B
29μA
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C
72μA
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D
29mA
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Solution

The correct option is C 29μA
As we know,
i=Qt=net=1.8×1014×1.6×1019=28.8×106A
=29μA

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