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Byju's Answer
Standard XII
Mathematics
Change of Variables
∫ a + cb + c ...
Question
∫
b
+
c
a
+
c
f
(
x
)
dx
is equal to
A
∫
b
a
f
(
x
−
c
)
dx
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B
∫
b
a
f
(
x
+
c
)
dx
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C
∫
b
a
f
(
x
)
dx
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D
∫
b
−
c
a
−
c
f
(
x
)
dx
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Solution
The correct option is
B
∫
b
a
f
(
x
+
c
)
dx
∫
b
+
c
a
+
c
f
(
x
)
dx
By putting x = t + c in the given expression, we get
∫
b
a
f
(
t
+
c
)
dt
=
∫
b
a
f
(
x
+
c
)
dx