a - cd - bc - ab -d

badc

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adab

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cdba

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acdb

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bacd

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Solution

The correct option is A badc
The sequence is a b c d / a b c d / a b c d Group of missing letter is b a d c

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Similar questions

Let ABCD be a quadrilateral with diagonals AC and BD. Prove the following statements (Compare these with the previous problem);

(a) AB + BC + CD > AD;

(b) AB + BC + CD + DA > 2AC;

(d) AB + BC + CD + DA > AC + BD.

In a trapezium ABCD, if AB || CD then $(A C^{2} + B D^{2})$ = ?

(a) $B C^{2} + A D^{2} + 2 B C . A D$

(b) $A B^{2} + C D^{2} + 2 A B . C D$

(d) $B C^{2} + A D^{2} + 2 A B . C D$

In the figure, prove that:

$(i) C D + D A + A B + B C > 2 A C$

$(i i) C D + D A + A B > B C$

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