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EMF and EMF Devices

A cell has te...

Question

A cell has terminal voltage $2 V$ in open circuit and internal resistance of the given cell is $2 Ω$ . If $4 A$ of current is flowing between points $P$ and $Q$ in the circuit and then the potential difference between $P$ and $Q$ is

A

22 V

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B

24 V

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C

30 V

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D

26 V

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Solution

The correct option is A $26 V$
Key Point : Find the terminal potential difference in case of charging a battery.
According to question, it is the case of charging of battery. So, terminal potential difference is given by
$T P D = V_{P} - V_{R} = E + I r = 2 + (4 \times 2)$ $= 10 V . . . . (i)$
Again, $V_{R} - V_{Q} = I R = 4 \times 4 = 16 V . . . . (i i)$
From Eqs. (i) and (ii), we get
$V_{P} - V_{R} + V_{R} - V_{Q} = 10 + 16 \Rightarrow V_{P} - V_{Q} = 26 V$

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