A cell of internal resistance r is connected across an external resistance nr. The the ratio of the terminal voltage to the emf of the cell is
A
1n
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B
1n+1
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C
nn+1
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D
n−1n
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Solution
The correct option is Cnn+1 Internal resistance =r, external resistance =nr Let E= emf of cell. Current drawn from cell is I=Er+nr If V be the terminal voltage , V=E−Ir=E−Er+nrr or VE=1−1n+1=nn+1