Question

A certain amount of gas at ${25}^{0}C$ and at a pressure of $0.80$ atm is contained in a glass vessel. Suppose that the vessel can withstand a pressure of $2.0$ atm. How high can you raise the temperature of the gas without bursting the vessel?

• A. ${745}^{0}C$
• B. ${472}^{0}C$
• C. ${500}^{0}C$
• D. None of these

Answer 1

Answer: (B)

${472}^{0}C$

$P_1=0.80$ atm

$T_1={25}^{\circ }C=25+273=298K$

$P_2=2atm$

$T_2=?$

Using - Gay - Lussac's law : $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$P\propto T\{$ at constant volume $\}$

We get,

$\frac{0.80}{298}=\frac{2}{T_2}$

$T_2=\frac{2\times 298\times 100}{80}=745K$. or ${472}^{o}C$