A certain compound contains calcium, carbon and nitrogen in the mass ratio $20 : 6 : 14$ . The empirical formula of the compound is:

C a C N

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C a_{2} C_{2} N

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C a (C N)_{2}

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C a C N_{2}

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Solution

The correct option is A $C a C N_{2}$
$C a : C : N = \frac{20}{40} : \frac{6}{12} : \frac{14}{14} = 1 : 1 : 2$

Hence, the empirical formula is $C a C N_{2}$ .

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