Question

A certain electrode has standard (reduction potential) of 0.384 V. The potential when measured against a normal calomel electrode (with electrode potential = 0.28 V) is:

• A. $0.104$
• B. $0.664$
• C. $0.332$
• D. $0.218$

Answer 1

Answer: (A)

$0.104$

$E_{{red}^n}^o=0.384V$ (cathode)

$E_{calomel}^o=\underset{}{\underset{}{0.28V}}$

less than 0.384V $\therefore$ it get oxidises (Anode)

$E_{cell}^o=E_C^o-E_A^o=0.384-0.28=0.104$