Question 6 A certain freezing process requires that room temperature be lowered from 40- C at the rate of 5- C every hour- What will be the room temperature 10 hours after the process begins-

Initial temperature = 40^∘C Change in temperature per hour = 5^∘C Change in temperature after 10 hours=( 5) × 10= 50^∘C Final temperature=40^∘C+( 50^∘C)= 10^∘C ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Integers

Question 6 A ...

Question

Question 6
A certain freezing process requires that room temperature be lowered from $40^{\circ} C$ at the rate of $5^{\circ} C$ every hour. What will be the room temperature 10 hours after the process begins?

Open in App

Solution

Initial temperature = $40^{\circ} C$
Change in temperature per hour = $- 5^{\circ} C$
Change in temperature after 10 hours= $(- 5) \times 10 = - 50^{\circ} C$
Final temperature= $40^{\circ} C + (- 50^{\circ} C) = - 10^{\circ} C$

Suggest Corrections

Similar questions

Q. A certain freezing process requires that room temperature be lowered from

40^{o} C

at the rate of

5^{o} C

every hour. What will be the room temperature

10

hours after the process begins?

Q. A certain freezing process requires that room temparature be lowered from

40^{o}

C at the rate of

5^{o}

C every hour. What will be the room temparature 10 hours after the process begins?

A certain freezing process requires that room temperature should be lowered from 40 $^{\circ}$ C at the rate of 5 $^{\circ}$ C every hour. What is the room temperature after 10 hours?

Join BYJU'S Learning Program

Explore more

Integers

Standard VII Mathematics

Join BYJU'S Learning Program

Question 6 A certain freezing process requires that room temperature be lowered from 40∘C at the rate of 5∘C every hour. What will be the room temperature 10 hours after the process begins?

Initial temperature = 40∘C Change in temperature per hour =−5∘C Change in temperature after 10 hours=(−5)×10=−50∘C Final temperature=40∘C+(−50∘C)=−10∘C

Question 6
A certain freezing process requires that room temperature be lowered from $40^{\circ} C$ at the rate of $5^{\circ} C$ every hour. What will be the room temperature 10 hours after the process begins?

Initial temperature = $40^{\circ} C$
Change in temperature per hour = $- 5^{\circ} C$
Change in temperature after 10 hours= $(- 5) \times 10 = - 50^{\circ} C$
Final temperature= $40^{\circ} C + (- 50^{\circ} C) = - 10^{\circ} C$