A certain freezing process requires that room temperature be lowered from 40-C at the rate of 5-C every hour- What will be the room temperature 10 hours after the process begins-

Initial temperature = 40^∘C Change in temperature per hour = 5^∘C Change in temperature after 10 hours = ( 5) × 10= 50^∘C Final temperature = 40^∘C+( 50^∘C) = ...

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Standard VII

Mathematics

Integers

A certain fre...

Question

A certain freezing process requires that room temperature be lowered from $40^{\circ} C$ at the rate of $5^{\circ} C$ every hour. What will be the room temperature 10 hours after the process begins?

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Solution

Initial temperature = $40^{\circ} C$
Change in temperature per hour = $- 5^{\circ} C$
Change in temperature after 10 hours = $(- 5) \times 10 = - 50^{\circ} C$
Final temperature = $40^{\circ} C + (- 50^{\circ} C) = - 10^{\circ} C$

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A certain freezing process requires that room temperature be lowered from 40∘C at the rate of 5∘C every hour. What will be the room temperature 10 hours after the process begins?

Initial temperature = 40∘C Change in temperature per hour = −5∘C Change in temperature after 10 hours = (−5)×10=−50∘C Final temperature = 40∘C+(−50∘C)=−10∘C

A certain freezing process requires that room temperature be lowered from $40^{\circ} C$ at the rate of $5^{\circ} C$ every hour. What will be the room temperature 10 hours after the process begins?

Initial temperature = $40^{\circ} C$
Change in temperature per hour = $- 5^{\circ} C$
Change in temperature after 10 hours = $(- 5) \times 10 = - 50^{\circ} C$
Final temperature = $40^{\circ} C + (- 50^{\circ} C) = - 10^{\circ} C$