A certain freezing process requires that room temperature be lowered from 40C at the rate of 5C every hour. What will be the room temperature 10 hours after the process begins?

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Solution

initial temperature = $40^{\circ} C$
Rate of change in temperature = $5^{\circ} C / h o u r$
time = 10 hours
So, in 10 hours the temp would be decreased
by $10 \times 5 = 50^{\circ} C$
So, final temperature = $40 - 50^{\circ} = - 10^{\circ} C$

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A certain freezing process requires that room temperature should be lowered from 40 $^{\circ}$ C at the rate of 5 $^{\circ}$ C every hour. What is the room temperature after 10 hours?

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A certain freezing process requires that room temperature be lowered from 40C at the rate of 5C every hour. What will be the room temperature 10 hours after the process begins?

initial temperature = 40∘CRate of change in temperature = 5∘C/hourtime = 10 hoursSo, in 10 hours the temp would be decreasedby 10×5=50∘CSo, final temperature = 40−50∘=−10∘C

initial temperature = $40^{\circ} C$
Rate of change in temperature = $5^{\circ} C / h o u r$
time = 10 hours
So, in 10 hours the temp would be decreased
by $10 \times 5 = 50^{\circ} C$
So, final temperature = $40 - 50^{\circ} = - 10^{\circ} C$