Question

A certain gaseous compound contains carbon and oxygen only (mol.wt. = 72.) present in the ratio of 1:2 by mass. The formula of the compound would be:

• A. $C{O}_2$
• B. $CO$
• C. $C_2{O}_3$
• D. $C_3{O}_4$

Answer 1

The correct option is C $C_2{O}_3$

Total molecular $wt=72$

$C$ & $O$ only

Let $Cu-O_4$ be the compound given,

$\frac{12\times x}{16\times y}=\frac{1}{2}$ $\Rightarrow y=\frac{3x}{2}$ ....... $1$

$12x+16y=72$ $\Rightarrow 3x+4y=18$

Putting $y$ from $1$

$9x=18$

$x=2$

$y=3$

$\therefore$ Answer is $C_2{O}_3$