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Question

A certain laser transition emits 6.37×1015 quanta per second per square metre. Calculate the power output in joule per square metre per second( Given λ=632.8nm):

A
3.14×1019Jm2 sec1
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B
4×103Jm2 sec1
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C
2×103Jm2 sec1
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D
4.03×109Jm2 sec1
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Solution

The correct option is C 2×103Jm2 sec1
Energy falling per square meter per second=No.of quanta falling per square meter per second\times Energy of one quanta
=6.37×1015×hc/λ
=6.37×1015×6.626×1034×108632.8×109
=2×103Jm2 sec1

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