Question

A certain mass of a gas occupies a volume of 0.2 ${dm}^3$ at 273K. Calculate the volume of the gas if its absolute temperature is doubled at the same pressure.

Answer 1

Given,

$T_1$= $273$ K

$V_1$= $0.2d{m}^3$

$T_2=2\times 273=546K$(if absolute temperature is doubled at the same pressure)

$V_2$=?

By Charles law,

$\frac{V_1}{V_2}=\frac{T_1}{T_2}$

$V_2=\frac{546}{273}\times 0.2d{m}^3$

$V_2=0.4d{m}^3$