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Question

A certain number gives a remainder 5 on dividing by 7 and a remainder 7 on dividing by 15. Find the smallest such number.

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Solution

Dear student
Let the required number be z.Then According to question,z=7x+5 and z=15y+77x+5=15y+77x=15y+2 ..(1)Here x=15n-2,y=7n-2 satsfies the eq(1)Putting n=1, we getx=15-2=13 and y=7-2=5So, z=15×5+7=82Thus, the smallest number which leaves remainder 5 and 7 when divided by7 and 15 respectively is 82.
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